# Simple math problem.. I think.. If I was good at math :)

By fritsl

September 5, 2012

September 5, 2012

I am going nuts over this (possibly) simple equation that I need for a fun Processing project.

I need to have the "calculation" or "equation" for** X**

**Y** is the number of times we go (X=X+X), and the end result should always be **1**

EXAMPLE:

IF Y is 2 then X = **0.25**, because

0.25+0.25=0.5 (Y1)

0.5+0.5=1 (Y**2**)

HOW on earth does one calculate X? (if Y is for example 214.7787009)?

I imagine it'd be something like X=1/SQR Fish Y Something Hotdog?!?

There's SO much respect to the person cracking this! :) (Or I'll delete the post and pretend this never happened, if the answer is really simple :)

Thanks :) (and respect)

## Don't know if you've managed

Don't know if you've managed to crack this yet, there is a lot of posts in this thread, and I cannot read them all!

But,

If I understand correctly, you're looking to find out for a value of y, with what size of x you can add x to itself y times to sum to 1?

So something along the lines of: 1 = (2^y)*x

Which if you know y, you can solve for x as: x = 1/(2^y)

So for y=4 for example that gives you x=0.0625

which would work out as

0.0625 + 0.0625 = 0.125

0.125 + 0.125 = 0.25

0.25 + 0.25 = 0.5

0.5 + 0.5 = 1

And for y=214.7787009 x=2.214E-65

But then I might be wrong about what it is you are after!

## I still not understand why

I still not understand why the term "y times" should represent an exponential function rather than a simple multiplication. In the link you will find the text "3 multiplied by 4 (often said as "3 times 4")".

But let's say, the term "y times" should represent, the addition (x+x=2x) shall be exponential repeated. Then we have to follow the exponential law:

This would lead to following euqation:

Solving for x

This means this equation has only one solution if y≠0. But that's not what was originally intended :)

## I AM to late to the party,

I AM to late to the party, sadness

## is it only for addition?

cause if it is only for addition/multiplication, then it is only limited to what the given X is

so.....you are looking for the formulae for x? hmmm...how about:

y=any number but not = to zero, since having zero calculations gives nothing :P

since y is the times of the number that is going to be calculated......y can be the addition of a number that ends up into 1

ie: A=0.25, Y=4, X=1, X=A x Y

0.25x4=1

or 0.25+0.25+0.25+0.25=1

X=gravity, since as you've said, yer gravity=1 and x=1...so it is fixed

so if you are looking for the calculation of the gravity, then. A is the object(or mass...i think) and Y is the distance

## hmm...not good in math...but...

lol, x+x=x? like 2+2=2 if x=2? hmm...should be undefined if the formula was that :P

if that was a typo...do you mean y=x+x? cause if it is, then if y=2, 2=1+1, x=1 :P

if you are asking about addition...then to know what x is, with a given y, then just devide the y into 2 and there you have the x :P

i.e:

x+x=y

y=214.7787009

x=?

formulae: y/2=x

sol'n: 214.7787009 / 2=107.3893505

checking: 107.3893505 x 2 or 107.3893505+107.3893505= 214.7787009

x=107.3893505

## I knew it will happen again.

I knew it will happen again. Just commented here http://letsmakerobots.com/node/34018#comment-91690 about "I am the smartest guy in the room" but have to face that I am not the one :-) Seems Markus is beating all of us also when birdmun and TH did a great job trying to explain higher maths :-)

For me it's just another unknown miracle how people can calculate such things. Ok, I am not the worst in math as I instantly saw the funny thing in Markus's example picture but if it's going to be complicated then I am trying to seek for other solutions.

What do you want to achieve with that formula Frits?

## To Lumi,

Don't calculate it, use a good scientific calculator :P Good ones have limits, differnetiation and integration in it as well!!

Or if you are a guy who likes it the old school way, I believe I can send you a copy of my class 12th Maths Book (if it still exists btw. Dunno, have to check).

## Shame on you, vishu, if you,

Shame on you, vishu, if you, who has this education, would need a scientific calculator to do such simple limit calculations. My most beloved Indian mathematician Srinivasa Ramanujan would be turning in his grave!!

## Dude, I don't need one...

Just that it can be done that way as well...

## To be fair, I have a

To be fair, I have a mathematician degree (B.Sc.) :P

If you want to take a look, Lumi, this is what I am doing beside robotics. Working on the Collatz conjecture.

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