# Simple math problem.. I think.. If I was good at math :)

By fritsl

September 5, 2012

September 5, 2012

I am going nuts over this (possibly) simple equation that I need for a fun Processing project.

I need to have the "calculation" or "equation" for** X**

**Y** is the number of times we go (X=X+X), and the end result should always be **1**

EXAMPLE:

IF Y is 2 then X = **0.25**, because

0.25+0.25=0.5 (Y1)

0.5+0.5=1 (Y**2**)

HOW on earth does one calculate X? (if Y is for example 214.7787009)?

I imagine it'd be something like X=1/SQR Fish Y Something Hotdog?!?

There's SO much respect to the person cracking this! :) (Or I'll delete the post and pretend this never happened, if the answer is really simple :)

Thanks :) (and respect)

## One more time from the top?

That's true.

Where did I say that x=0?

True, that's what I was trying to point out. When Frits used x=x+x he meant it as a programming instruction and that's how I interpreted it, not as an equation.

When I said:

I was just trying to reply to:

I was trying to point out that x=x+x can be interpreted as an ecuation and if you do, the solution is x=0.

## You have even a problem with

You have even a problem with x=0, because then you have a possible 0 through 0 divison which is not defined in some domains, but anyhow, that's another topic.

So let's simply say, z=2x, to avoid all the problems.

Frits now defies the operation z should be performed y-times and the result of the multiplication should always be 1, which simply means yz=1 <=> 2xy=1.

Can you try to derivate your formula from Frits definition in a common mathematical way that I can see how you came to an exponential equation?

I guess Frits wanted to compute the gravitational force between his dick and Mars but failed to explain it in a proper way :P

## We're getting closer

That's the problem right there. The operation z (z=2x) performed y-times does not mean multiply z by y. On each step the x changes and the next step will double the new value.

so if y is 3 you get something like: (2*(2*(2*x)))

for y=4 you get (2*(2*(2*(2*x))))

for y=5 you get (2*(2*(2*(2*(2*x)))))

-> since we don't need the parens we can write this as 2*2*2*2*2*x or (2^5)*x

## y-times is defined as a

y-times is defined as a simple multiplication according to the propositional logic, otherwise you would define the variable not as y, but let Frits simply do a lookup table with some x/y values. Then we are more clear what he wants to compute. Topic closed for me as long as the definitions and notations are ambiguous which is detrimental to any serious discussion.

## Would I be correct in

## I knew it will happen again.

I knew it will happen again. Just commented here http://letsmakerobots.com/node/34018#comment-91690 about "I am the smartest guy in the room" but have to face that I am not the one :-) Seems Markus is beating all of us also when birdmun and TH did a great job trying to explain higher maths :-)

For me it's just another unknown miracle how people can calculate such things. Ok, I am not the worst in math as I instantly saw the funny thing in Markus's example picture but if it's going to be complicated then I am trying to seek for other solutions.

What do you want to achieve with that formula Frits?

## To be fair, I have a

To be fair, I have a mathematician degree (B.Sc.) :P

If you want to take a look, Lumi, this is what I am doing beside robotics. Working on the Collatz conjecture.

## I know that you are a

I know that you are a mathematician Markus :-) (but had to google B.Sc.just now)

What I don't like is something endless to the top....I like defined areas/ranges/numbers with an END.

So I want to know what Frits is planning with this calculation.

//Edit: This article in the link is from you...got you because of the very unique username :)

## "So I want to know what

"So I want to know what Frits is planning with this calculation."

I just needed to be able to insert predicted gravity in time&space in an virtual invironment, while learning Processing, and having frantic spasms and tics. (Don't ask me, nothing makes sense, I work and play by intuition :)

The number 1 is gravity 1 at "the edge" of a given object. Y is the distence to the object. X's are amount of gravity, relative to 1 at the surface. My mind flew from space, and was now affected by X, as an object came closer. I knew the distance to the object, Y - but how much gravity should I feel, I was wondering :D The answer was X!

## Oh - and "endless at the

Oh - and "endless at the top": All in universe is affecting all. That is why. But my dick is only affecting Mars with very.. very small numbers. Very!

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